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Question

In the Carius method for the estimation of halogen, 0.18 g of an monobromo organic compound gave 0.12 g of AgBr. The percentage of bromine in the compound is:
(Atomic mass of Br = 80 u, Ag = 108 u)

A
54.04%
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B
42.54%
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C
28.36%
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D
14.18%
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Solution

The correct option is C 28.36%
(Given: Atomic mass of Br = 80 u, Ag = 108 u)

Molar mass of bromine = 80 g/mol
Molar mass of AgBr = 188 g/mol
Mass of AgBr = 0.12 g
Mass of organic compound = 0.18 g

mass of the organic compoundmass of AgBr=molar mass of the organic compound molar mass of AgBr

0.180.12=molar mass of the organic compound188

0.18×1880.12=molar mass of the organic compound

the % of bromine in the organic compound,= molar mass of Brmolar mass of the organic compound×100

=80×0.120.18×188×100=28.36%

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