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Mixed Combination of Cells

In the circui...

Question

In the circuit of given figure, the final voltage drop across the capacitor C is:

\frac{V r_{1}}{r_{1} + r_{2}}

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\frac{V r_{2}}{r_{1} + r_{2}}

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\frac{V (r_{1} + r_{2})}{r_{2}}

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\frac{V (r_{1} + r_{2})}{r_{1} + r_{2} + r_{3}}

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Solution

The correct option is B $\frac{V r_{2}}{r_{1} + r_{2}}$
In steady state, the capacitor arm produce an infinite resistance. So, the potential difference across C is that across $r_{2}$ .
So, current through $r_{2} = \frac{V}{(r_{1} + r_{2})}$
Potential difference across $r_{2} = \frac{V (r_{2})}{(r_{1} + r_{2})}$

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In the circuit of given figure, the final voltage drop across the capacitor C is:

The correct option is B Vr2r1+r2In steady state, the capacitor arm produce an infinite resistance. So, the potential difference across C is that across r2.So, current through r2=V(r1+r2)Potential difference across r2=V(r2)(r1+r2)