Question

# In the circuit of given figure, the final voltage drop across the capacitor C is:

A
Vr1r1+r2
B
Vr2r1+r2
C
V(r1+r2)r2
D
V(r1+r2)r1+r2+r3

Solution

## The correct option is B $$\displaystyle \frac{Vr_2}{r_1 + r_2}$$In steady state, the capacitor arm produce an infinite resistance. So, the potential difference across C is that across $$r_2$$.So, current through $$\displaystyle r_2 = \frac{V}{(r_1 + r_2)}$$Potential difference across $$\displaystyle r_2 = \frac{V(r_2)}{(r_1 + r_2)}$$Physics

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