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Question

In the circuit shown here the transistor used has a current gain $$\beta =100$$. What should be the bias resistor $$R_B$$ so that $$V_{CE}=5$$V (neglect $$V_{BE}$$).
693016_2947524891444165afd8bceefb26ef47.jpg


A
200×103Ω
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B
1×106Ω
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C
500Ω
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D
2×103Ω
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Solution

The correct option is A $$200\times 10^3\Omega$$
Applying Kirchhoff's law to mesh ADCEFA
$$V_{CC}=10=I_C\times 10^3+V_{CE}$$
$$10=I_C\times 10^3+5$$
$$I_C=5\times 10^{-3}A$$              .......(i)
Applying Kirchhoff's law to mesh AGBEFA
$$I_B\times R_B+V_{BE}=V_{CC}=10$$V
$$I_B\times R_B+0=10$$               ........(ii)
$$5\times 10^{-5}\times R_B=10$$
$$R_B=2\times 10^5\Omega =200\times 10^3\Omega$$.
722061_693016_ans_2311b7983422443aa80b0644841949f2.jpg

Physics

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