In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across $6 Ω$ resistance is $V_{A} - V_{B} = 10 V .$

The current in the 4.00 resistance between C & B is 5A.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The unknown emf

E_{1}

is 36 V.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The unknown emf

E_{2}

is 54 V.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The resistance R is equal to 9

Ω

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A The unknown emf $E_{2}$ is 54 V.
B The resistance R is equal to 9 $Ω$
C The unknown emf $E_{1}$ is 36 V.
D The current in the 4.00 resistance between C & B is 5A.
After redrawing the circuit
$(a) I_{4} = 5 A$
(b) From loop (1)
$- 8 (3) + E_{1} - 4 (3) = 0 \Rightarrow E_{1} = 36$ volt
from loop (2)
$+ 4 (5) + 5 (2) - E_{2} + 8 (3) = 0$
$E_{2} = 54$ volt
(c) from loop (3)
$- 2 R - E_{1} + E_{2} = 0$
$R = \frac{E_{2} - E_{1}}{2} = \frac{54 - 36}{2} = 9 Ω$

Suggest Corrections

Similar questions

Q. In the circuit shown in figure,

E_{1}

and

E_{2}

are two ideal sources of unknown emfs. Current flowing through resistor of resistance

R Ω

2 A

and through resistor of resistance

4 Ω

3 A

as shown. If potential difference across

6 Ω

resistance is

V_{A} - V_{B} = 10 V

, then the value of

(E_{2} - E_{1}) R

( in

V . Ω

) is

In the circuit shown in figure, a 12 V power supply with unknown internal resistance $r$ is connected to a battery with unknown emf $E$ and internal resistance 1 $Ω$ and to a resistance of 3 $Ω$ carrying a current of $2 A$ . The current through the rechargeable battery is $1 A$ in the direction shown. Find the unknown current $i$ , internal resistance $r$ and the emf $E$ .