Question

In the circuit shown in figure, find the current through the branch BD

• A. 5 A
• B. 0 A
• C. 3 A
• D. 4 A

Answer 1

The correct option is A 5 A


The current in the circuit are assumed as shown in the fig.
Applying KVL along the loop ABDA, we get
$-6i-3i_2+15=0$ or $2i_1+i_2=5$ .........(i)
Applying KVL along the loop BCDB, we get
$-3(i_1-i_2)-30+3i_2=0$ or $-i_1+2i_2=10$ .........(ii)
Solving equation (i) and (ii) for $i_2$, we get $i_2=5A$