Question

In the circuit shown in figure, find the value of R(in $\Omega$), so that the current through $15$ volts
battery is zero

• A. 15.00
• B. 15
• C. 15.0
• D. $15.00$

Answer 1

Answer: (A), (B), (C), (D)

If current through $15V$ battery is zero, then potential difference across R would be $15V.$
So,
$\left(\frac{25}{10+R}\right)R=15;\Rightarrow 15\Omega$