Question

In the circuit shown in figure. The reading of ammeter A is

• A. 0.2 A
• B. 0.4 A
• C. 0.6 A
• D. 0.8 A

Answer 1

The correct option is B

0.4 A

Resistors of resistance 6Ω, 3Ω and 2Ω are in parallel.

Their equivalence resistance r is given by $\frac{1}{r}=\frac{1}{6}+\frac{1}{3}+\frac{1}{2}=r=1\Omega$

This resistance r is in series with the $4\Omega$ resistance. Therefore, the resistance in series with the ammeter is $R=1+4=5\Omega \therefore current=\frac{2}{5}=0.4A$