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Question

In the circuit shown in the figure, C=6 μF. The charge stored in capacitor of capacity C is-

A
Zero
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B
90 μC
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C
40 μC
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D
60 μC
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Solution

The correct option is C 40 μC

Here, C and 2C are in series, so same amount of charge will be stored in both the capacitor.

On going from A to B, we get,
VA+10Q2CQC=VB

0+103Q2C=0 [A and B are grounded]

Q=20C3=20×63=40 μC

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