Question

# In the circuit shown in the following figure, the switch is kept closed for a long time and then opened at t = 0. The values of the current just before opening the switch (t=0−) are, respectively.

A
34Aand1A
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B
76Aand52A
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C
1Aand76A
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D
1 A and 1 A
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Solution

## The correct option is C 1Aand76Aat t=0− The inductor will be short, ∴i=3020+10A=1A and current through inductor at t=0+ IL=1A From the figure, Applying KVL in outer loop. 30=(20+20)I+20i ....(i) As the current through the inductor does not change instantaneously. The current the inductor will be 1 A at t = 0+ i=(I+1) 30=40I+20I+20 I=1060=16 Hence current, i=I+1=16+1=76A

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