Question

# In the circuit shown, the point $$'B'$$ is earthed. The potential at the point $$'A'$$ is

A
14 V
B
24 V
C
26 V
D
50 V

Solution

## The correct option is B $$24\ V$$$$i=\dfrac { 50 }{ 5+7+10+3 } =2A$$Potential difference between $$A$$ and $$B$$$$V_A-V_B=2\times 12$$$$\implies V_A-0=24$$$$\therefore V_A=24$$Physics

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