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Question

In the circuit shown, the point $$'B'$$ is earthed. The potential at the point $$'A'$$ is
953831_d0d9022847da4084a7c6cefe17cd27c8.png


A
14 V
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B
24 V
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C
26 V
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D
50 V
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Solution

The correct option is B $$24\ V$$
$$i=\dfrac { 50 }{ 5+7+10+3 } =2A$$
Potential difference between $$A$$ and $$B$$
$$V_A-V_B=2\times 12$$
$$\implies V_A-0=24$$
$$\therefore V_A=24$$

Physics

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