    Question

# In the circuit shown, the resistance are given in ohms and the battery is assumed ideal with emf equal to 3.0 volts. The resistor that dissipates the most power is- A
R1
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B
R2
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C
R3
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D
R4
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Solution

## The correct option is A R1Given circuit can be simplified as, V1=5050+1007×3⇒150450×7=73V V2=3−73=23V Power dissipated through resistance R1 is power P1=V21R1=499×50=49450V R2,R3 and R4 have same potential and R4 is least among them ∴ Power in R4> Power in R2,R3 Power dissipated through resistance R4 is ∴ Power P4=V22R4 Power P4=49×30=4270V ∴ Power dissipated in R1 is max.  Suggest Corrections  1      Similar questions
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