In the compound lithium tetrahydroaluminate, the ligand is

H^{+}

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H^{-}

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H

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None of these

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Solution

The correct option is A $H^{-}$
Lithium tetrahydroaluminate is $L i [A l (H)_{4}]$ . In the compound lithium tetrahydroaluminate, the ligand is $H^{-} .$

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Similar questions

l + \{h \times \frac{(\frac{N}{2} - c f)}{f}\}

l + \{h \times \frac{(c f - \frac{N}{2})}{f}\}

l - \{h \times \frac{(\frac{N}{2} - c f)}{f}\}

C O, N O, C_{2} H_{4}, C

_{3}

_{5}^{-}

H^{-}

C + H_{2} O \to C O + H_{2}

H_{2} O

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