Question

# In the diagram given below $$\angle EDC$$. The tangent drawn to the circle at $$C$$ makes an angle of $${50}^{o}$$ with $$AB$$ produced. Find the measure of $$\angle ACB$$.

Solution

## $$\angle{AGE}={50}^{\circ}$$Consider $$AC$$ diameterIn $$\triangle{ACG},\angle{ACG}={90}^{\circ}$$$$\Rightarrow \angle{CAG}={40}^{\circ}$$ $$(sum~ of ~angle ~in ~triangle)$$In $$\triangle{ACB},\angle{CAB}={40}^{\circ}$$$$\Rightarrow \angle{ACB}={50}^{\circ}$$Mathematics

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