Question

In the diagram given below $\angle EDC$. The tangent drawn to the circle at $C$ makes an angle of ${50}^o$ with $AB$ produced. Find the measure of $\angle ACB$.

Answer 1

$\angle AGE={50}^{\circ }$

Consider $AC$ diameter

In $△ACG,\angle ACG={90}^{\circ }$

$\Rightarrow \angle CAG={40}^{\circ }$ $\left(sumofangleintriangle\right)$

In $△ACB,\angle CAB={40}^{\circ }$

$\Rightarrow \angle ACB={50}^{\circ }$