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Question

In the expansion of (1xx2+x3)6, the sum of the coefficients of x is


A
0
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B
1
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C
2
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D
3
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Solution

The correct option is A 0
f(x)=(1xx2+x3)6
Sum of coefficients of x is f(1)
f(1)=(111+1)6=0

Note :
1) Sum of the coefficients of even powers of x is f(1)+f(1)2
2) Sum of the coefficients of odd powers of x is f(1)f(1)2

Mathematics

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