Question

In the fig. given below, the current passing through $6\Omega$ resistor is

• A. 0.40 amp
• B. 0.48 amp
• C. 0.72 amp
• D. 0.80 amp

Answer 1

The correct option is B 0.48 amp

Voltage across the two resistors connected in parallel is same.

$\therefore$ $I\left(6\right)=(1.2-I)4$

$⟹$ $I=\frac{4.8}{10}=0.48$ A