CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

In the fig. $$S1$$ and $$S2$$ are identical springs. The oscillation frequency of mass $$m$$ is $$f$$. If one spring is removed, the frequency will become
192311_3bd93063a6f8477ab2a4b9f8e6eb46cf.png


A
f
loader
B
f×2
loader
C
f×2
loader
D
f/2
loader

Solution

The correct options are
C $$f\times\sqrt{2}$$
D $$f/\sqrt{2}$$
For the given figure $$f=\dfrac{1}{2\pi}\sqrt{\dfrac{k_{eq}}{m}}=\dfrac{1}{2\pi}\sqrt{\dfrac{2k}{m}}$$    .....(i)
If one spring is removed, then $$k_{eq}=k$$ and 
$$f'=\dfrac{1}{2\pi}\sqrt{\dfrac km}$$   .....(ii)
From equation (i) and (ii), $$\dfrac{f}{f'}=\sqrt 2\Rightarrow f'=\dfrac{f}{\sqrt 2}$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image