In the fig- the potentiometer wire AB of length L resistance 9 r is joined to the cell D of e-m-f- - and internal resistance r- The cell Cs e-m-f- is - -2 and its internal resistance is 2 r- The galvanometer G will show no deflection then find length AJ-

Let at x distance it will show no deflection then current on AB=ε10r In case of no deflection 9rLX×ε10r=ε10r So, x=5L9 ...

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Standard XII

Physics

EMF and EMF Devices

In the fig. t...

Question

In the fig. the potentiometer wire $A B$ of length $L$ & resistance $9 r$ is joined to the cell $D$ of e.m.f. $ε$ and internal resistance $r$ . The cell $C s$ e.m.f. is $ε / 2$ and its internal resistance is $2 r$ . The galvanometer $G$ will show no deflection then find length $A J$ :

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Solution

Let at x distance it will show no deflection-
then current on $A B = \frac{ε}{10 r}$
In case of no deflection-
$\frac{9 r}{L} X \times \frac{ε}{10 r} = \frac{ε}{10 r}$
$S o, x = \frac{5 L}{9}$

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In the figure, the potentiometer wire AB of length L & resistance 9r is joined to the cell D of emf E & internal resistance r. The emf of the cell C is E / 2 & its internal resistance is 2r. The galvanometer G will show no deflection when the length AM is

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In the fig. the potentiometer wire AB of length L & resistance 9 r is joined to the cell D of e.m.f. ε and internal resistance r. The cell Cs e.m.f. is ε/2 and its internal resistance is 2 r. The galvanometer G will show no deflection then find length AJ:

Let at x distance it will show no deflection-then current on AB=ε10rIn case of no deflection-9rLX×ε10r=ε10rSo,x=5L9

In the fig. the potentiometer wire $A B$ of length $L$ & resistance $9 r$ is joined to the cell $D$ of e.m.f. $ε$ and internal resistance $r$ . The cell $C s$ e.m.f. is $ε / 2$ and its internal resistance is $2 r$ . The galvanometer $G$ will show no deflection then find length $A J$ :

Let at x distance it will show no deflection-
then current on $A B = \frac{ε}{10 r}$
In case of no deflection-
$\frac{9 r}{L} X \times \frac{ε}{10 r} = \frac{ε}{10 r}$
$S o, x = \frac{5 L}{9}$