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Question

In the figure a potential of 1200V is given to point A and point B is earthed, what is the potential at the point P?


  1. 800V

  2. 200V

  3. 400V

  4. 100V


Solution

The correct option is C

400V


3μF and 6μF are connected in series
q3=q6C1V1=C2V23(1200VP)=6(VPVB)
VB=0 [Grounded]
1200VP=2VP3VP=1200VP=400V

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