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Question

In the figure, AC = 10cm, PC = 15cm, PQ = 12cm, find PB.


  1. 6cm

  2. 7cm

  3. 8cm

  4. 9cm


Solution

The correct option is D

9cm


In ABC and PQC
PQC=ABC=90
C=C (common angle)
Therefore, ABCPQC by AA similarity
ACPC=ABPQ1015=AB12AB=8cm
In ABC ,
AB2+BC2=AC2BC=6cm
PB = PC – BC = 15 - 6 = 9 cm

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