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Question

IN the figure, AOB=90,AC=BC,OA=12 cm and OC = 6.5 cm. Find the area of AOB


Solution

IN AOB,AOB=90
C is a point on AB such that AC = BC join OC

Since C is the mid point of hypotenuse of right AOB   
AC=CB=OC=6.5cmAB=6.5+6.5+6.5=13cmNow in right AOBAB2=AO2+OB2(13)2=(12)2+OB2169=144+OB2OB2=169144=25=(5)2OB=5cmNow area of AOB=12Base×Altitude=12×OB×AO=12×5×12=30cm2
 

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