Question

In the figure, area of parallelogram is $64m^2.$ Its sides are 16 m and 8 m. Find the height $h_1$ and $h_2.$

• A. $h_1=4m,h_2=5m$
• B. $h_1=9m,h_2=8m$
• C. $h_1=8m,h_2=4m$
• D. $h_1=8m,h_2=5m$

Answer 1

The correct option is C $h_1=8m,h_2=4m$

Area of parallelogram = base $\times$ height
Given Area $=64m^2,$ sides 16 m and 8 m
When base = 8 m
Area = base $\times$ height($h_1$)
$64m^2=8m\times h_1$
$h_1=\frac{64}{8}$
$h_1=8m$

When base = 16 m
Area = base $\times$ height ($h_2$)
$64m^2=16m\times h_2$

$h_2=\frac{64}{16}$
$h_2=4m$