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Question

In the figure BD = DC and DBC=25. What is the value of BAC?

A
30
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B
100
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C
50
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D
90
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Solution

The correct option is B 50
Since, BD = DC in ΔBDC
Therefore, ΔBDC is an isosceles Δ.
Now, by the property of isosceles Δ.
DBC=DCB=25
Now, BDC=18050=130 (Sum of angles of Δ=180)
Now, ABCD is a cyclic quadrilateral
D+A=180
130+A=180
A=BAC=50

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