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Question

In the figure below, lines AB and CD intersect at O. If AOC + BOE = 70 and BOD = 40, find (3BOE).


A

30

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B

60

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C

90

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D

180

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Solution

The correct option is C

90


AOC + BOE + COE = 180 (Angles on a straight line equals 180)

Given, AOC + BOE = 70

So, COE = 180 - (AOC + COE) = 180 - 70= 110

Again, COE + BOE + BOD = 180 (Angles on a straight line equals 180)
We know that, COE = 110 and BOD = 40

So, BOE = 180 - COE - BOD= 180 - 110 - 40 = 30
3 × ( BOE) = 90


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