In the figure below- OP- OQ- OR and OS are four rays- Then- find - POQ - - QOR - - SOR - - POS-3-

∠ POQ + ∠ QOR + ∠ SOR + ∠ POS = 360^∘ ....(the sum of the angles around a point = 360^∘) So, (∠ POQ + ∠ QOR + ∠ SOR + ∠ POS)/3 = 360^∘/3 = ...

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Angles about a Point

In the figure...

Question

In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

$60^{\circ}$

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$0^{\circ}$

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$90^{\circ}$

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$120^{\circ}$

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Solution

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In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

O P, O Q, O R

O S

∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S = 360^{o}

\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}

In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

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