Question

# In the figure, block m1 is loaded on block m2. If there is no relative sliding between the blocks and the inclined plane is smooth, the frictional force acting between the blocks is:

A
μm2sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
μm1cosθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
μm1sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D ZeroAssuming no friction between the surfaces, acceleration of block 1 is Since, the blocks can only move along the inclined plane, so all forces ⊥ to inclined plane will be balanced for respective blocks. Acceleration of both blocks down the inclined plane is: a1=Net Forcemass=m1gsinθm1=gsinθ Acceleration of block 2 a2=Net Forcemass=m2gsinθm2=gsinθ ⇒ relative acceleration between blocks 1 and 2 is: (a1−a2)=(gsinθ−gsinθ)=0 Hence, we can say that there is no tendency of slipping between blocks, as both will move with same acceleration down the incline. ∴frictional force f=0 between block 1 and block 2.

Suggest Corrections
0
Join BYJU'S Learning Program
Select...
Related Videos
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
Select...