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Question

In the figure given, ABCD. Find the value of x in each case.
1715282_6b4bf4ebd7034629ad77715eb76f41bc.png

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Solution


Draw a line EF which is parallel to CD

So we get

EFCD and EC is transversal

from the figure we know that FEC andECD are
consecutive angles

so we get

FEC+ECD=180o

by substituting the values

FEC+124o=180o

FEC=56o

we also know that EFCD and ABCD

so we get EFAB and AE is a transversal

from the figure we know that BAE and FEA are
consecutive angles

so we get

BAE+FEA=180o

by substituting the values

116o+FEA=180o

FEA=64o

In order to find the value of x

xo=FEA+FEC

by substituting the values

xo=64o+56o

xo=120o

Therefore the value of x is 120

1564593_1715282_ans_9e586440c0804197a16775534fc74a60.png

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