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Question


In the figure given above, the ratio Area of DPQCArea of ABCD =____.

A
1
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B
12
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C
23
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D
13
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Solution

The correct option is C 23

Let h be the height between the parallel lines AB and CD

PQ=13AB

Hence, area of DPQC = 12×h times(PQ+DC)

= h2×(DC+AB3)

= h2×(DC+DC3)

= h2×(4DC3)

=2h×DC3

Now, we know that h×DC= area of parallelogram ABCD

Hence, area of trapezium DPQC = 23× area of parallelogram ABCD

Thus,Area of DPQCArea of ABCD=23

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