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Question

In the figure given below if O is the centre of the circle, ¯¯¯¯¯¯¯¯AB is the diameter and AD is produced to the point C then find ACB
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A
15
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B
30
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C
45
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D
60
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Solution

The correct option is D 60
Given that:
DOB=80,DBC=30
To find:
ACB=?
Solution:
Since, AB is a diameter.
So, ADB=90
ADB+BDC=180 (Linear pair)
or, BDC=18090=90
In BDC
BDC+DBC+DCB=180
or, 90+30+DCB=180
or, DCB=180120=60
ACB=DCB=60
Hence, D is the correct option.

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