In the figure given below, two parallelograms ABCD and PQCD lie on the same base CD and between the same parallel lines AQ and CD. Then, ā³APD and ā³BQC are congruent
We know parallelograms on the same base and between the same parallels are equalin area.
Thus, Area //gm DABC = Area //gm DPQC
Area △APD + Area trapezium DPBQ = Area trapezium DPBQ + Area △APD
Area △APD = Area △APD
Also AP + PB = PB + BQ
Thus, AP = BQ
Also, AD = BC and DP = CQ ... (opposite sides of a parallelogram)
△APD≅△BQC ....(by SSS criterion)