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Question

In the figure given below, two parallelograms ABCD and PQCD lie on the same base CD and between the same parallel lines AQ and CD. Then, ā–³APD and ā–³BQC are congruent


A
True
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B
False
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Solution

The correct option is A True

We know parallelograms on the same base and between the same parallels are equalin area.
Thus, Area //gm DABC = Area //gm DPQC
Area APD + Area trapezium DPBQ = Area trapezium DPBQ + Area APD
Area APD = Area APD

Also AP + PB = PB + BQ
Thus, AP = BQ

Also, AD = BC and DP = CQ ... (opposite sides of a parallelogram)

APDBQC ....(by SSS criterion)


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