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Question

In the figure, if OAB=40, ACB is equal to



A
50
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B
12AOB
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C
60
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D
70
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Solution

The correct options are
A 50
B 12AOB
In Δ OAB,                  
OA =  OB  [radii]
OAB=OAOBA=40
[angles opposite to equal sides are equal]
Also,      
AOB+40+40=180
[angle sum property of a triangle]
  AOB+40+40=180
  AOB=18080=100
We know that, in a circle, the angle subtended by an arc at the centre is twice the angle subtended by it at the remaining part of the circle.
AOB=2ACB
100=2ACB
ACB=1002=50

Mathematics

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