Question

In the figure, if CP || DQ, then the measure of x is

Answer 1

In the figure, CP||DQ
BA is transversal
Produce PC to meet BA at D

$\because QB||PD$
$\therefore \angle D={105}^0$ (Corresponding angles)
In $\Delta ADC$,
Ext. $\angle ACP=\angle CDA+\angle DAC$
$\Rightarrow x=\angle 1+{25}^0$
=${105}^0+{25}^0={130}^0$