Question

In the figure, l, m and n are parallel lines intersected by transversal p at X, Y and Z respectively. Find $\angle 1,\angle 2$ and $\angle 3$.

Answer 1

l || m|| n and p is then transversal which intersects then at X, Y and Z respectively
$\angle 4={120}^0$
$\angle 2=\angle 4$ (Alternate angles)
$\therefore \angle 2={120}^0$
But $\angle 3+\angle 4={180}^0$ (Linear pair)
$\Rightarrow \angle 3+{120}^0={180}^0\Rightarrow \angle 3={180}^0-{120}^0$
$\therefore \angle 1={60}^0$
Hence $\angle 1={60}^0,\angle 2={120}^0,\angle 3={60}^0$