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Question

In the figure m1=4m2. The pulleys are smooth and light. At time t=0, the system is at rest. If the system is released, the acceleration of mass m1 is
3715_19b520b577264c68804213183e6af435.png

A
g2
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B
g8
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C
g4
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D
g
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Solution

The correct option is B g4
when the body of mass 'm1' goes upward for distance 'x', it will free the string for mass 'm2' upto length '2x'
Therefore let acceleration of body m1=a
So, acceleration of body of mass m2=2a
for 'm1' force equation will be
m1g2T=m1a(equation1)
for
Tm2g=2m2a(equation2)
Solving the two equations and using the relation m1=4m2
we get a=g/4

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