In the figure, PC is the tangent to the circle. A and B are 2 points on the circle. If ∠BPC = 600 and ∠APB = 550, then find ∠ABP .
Using Tangent-Chord theorem, ∠APD = ∠ABP
Therefore ∠ABP = 1800 – 550 – 600
If PA and PB are two tangents to a circle with centre O such that ∠ AOB = 110o then ∠ APB is equal to
(a) 55o (b) 60o (c) 70o (d) 90o
If tangents PA and PB from a point P to a circle with centre O are inclined each other an angle of 70o, then find ∠POA
In the given figure, O is the centre of a circle. Then ∠OAB=?