You visited us 1 times! Enjoying our articles? Unlock Full Access!

Pulley

In the figure...

Question

In the figure shown, find the tension $T_{1}$ in the string. Take $g = 10 m / s^{2}$

2 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $4 g$
Since $10 k g > (2 + 3) k g$ , the $10 k g$ mass will move downward.

Acceleration of the system
$a = \frac{Supporting mass - Opposing mass}{Total mass}$
$= \frac{10 g - 5 g}{15} = \frac{g}{3} m / s^{2}$

FBD of $3 k g$ mass :

$T_{1} - 3 g = 3 a$
$\Rightarrow T_{1} = 3 (\frac{g}{3}) + 3 g = 4 g N$

Suggest Corrections

Similar questions

T_{1}

N

u = \sqrt{7 g l}

3 kg

θ = 180^{\circ}

g = 10 {m/s}^{2}

T_{1}

T_{2}

g = 10 {m/s}^{2}

T_{1}

g = 10 m / s^{2}

2 k g

3 k g

g = 10 m / s^{2}

Join BYJU'S Learning Program