In the figure, the potentiometer wire of length 1000 cm and resistance 9 ohm is joined to a cell of emf 2V and internal resistance of 1 ohm. The galvanometer G will show null deflection when the length AC is

75.0 cm

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800.0 cm

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833.3 cm

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850 cm

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Solution

The correct option is C 833.3 cm
Since the galvanometer shows null deflection, the pd across AC is 1.5 V. Hence ,
$1.5 = (\frac{2}{1 + 9}) \frac{9}{1000} (A C)$ . Hence AC = 833.3 cm

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