In the following circuit E 1-4 V - R 1-2 -E 2-6 V - R 2-2 - and R 3-4 - The current i 1 isA- 1-8 AB- 2-25 AC- 1-6 AD- 1 A

The correct option is A 1.8 A For loop (1) 2 i_1 2(i_1 i_2) + 4 = 0 ⇒ 2 i_1 i_2 = 2 ......(i) For loop (2) 4i_2 + 2(i_1 i_2) + 6 = 0 ⇒ 3 i_2 i_ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Combination of Resistors

In the follow...

Question

In the following circuit $E_{1} = 4 V, R_{1} = 2 Ω$
$E_{2} = 6 V, R_{2} = 2 Ω$ and $R_{3} = 4 Ω$ . The current $i_{1}$ is

1.6 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.8 A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.25 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω

R_{3} = 2 Ω

I_{1}

E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω

R_{3} = 2 Ω

I_{1}

E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω

R_{3} = 2 Ω .

l_{1}

E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω

R_{3} = 2 Ω

I_{1}

E_{1} = 3 V, E_{2} = 2 V, E_{3} = 6 V, R_{1} = 2 Ω, R_{4} = 6 Ω, R_{3} = 2 Ω, R_{2} = 4 Ω, C = 5 μ F

Join BYJU'S Learning Program