In the following compound, the number of sp hybridised carbons are:
$\begin{matrix} C H_{2} = C = C H & - & C H & - & C & \equiv & C H | C N \end{matrix}$

2

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3

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4

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5

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Solution

The correct option is C $4$
In the given compound, the number of sp-hybridised carbons are 4.
Hence,option C is correct.

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In the following compound, the number of sp hybridised carbons are:CH2=C=CH−CH−C≡CH|CN

The correct option is C 4In the given compound, the number of sp-hybridised carbons are 4.Hence,option C is correct.

In the following compound, the number of sp hybridised carbons are:
$\begin{matrix} C H_{2} = C = C H & - & C H & - & C & \equiv & C H | C N \end{matrix}$

The correct option is C $4$
In the given compound, the number of sp-hybridised carbons are 4.
Hence,option C is correct.