In the following compounds, the decreasing order of basic strength will be:

C_{2} H_{5} N H_{2} > N H_{3} > (C_{2} H_{5})_{2} N H

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N H_{3} > C_{2} H_{5} N H_{2} > (C_{2} H_{5})_{2} N H

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(C_{2} H_{5})_{2} N H > C_{2} H_{5} N H_{2} > N H_{3}

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(C_{2} H_{5})_{2} N H > N H_{3} > C_{2} H_{5} N H_{2}

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Solution

The correct option is C $(C_{2} H_{5})_{2} N H > C_{2} H_{5} N H_{2} > N H_{3}$
More stable the conjugate acid that will be formed, more is the basic strength of the amine. +I groups can stabilize the carbocation by pushing the electron density onto the electropositve nitrogen. Thus, the proper order of the decreasing basic strength is: $(C_{2} H_{5})_{2} N H > C_{2} H_{5} N H_{2} > N H_{3}$

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