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Question

# In the following figure, the p.d. between the points M and N is balanced at 50 cm. length. The length in cm, balancing for the potential difference between points N and C will be –

A
40
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B
100
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C
75
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D
25
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Solution

## The correct option is B 100Suppose the current flowing in the secondary circuit is I. Resistance across MN=4.44+4=2 Ω Then, VMN=I(2 Ω)=(50x cm) Since the balancing length is 50x cm, let the balancing length is L cm, this means, VNC=I(4Ω)=Lx cm VMNVNC=2I4I⇒50xLx=12 This means L=100 cm.

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