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Question

In the following reaction, how many moles of KI react with 12.5 mol of K2S2O8?
K2S2O8(aq)+2KI(aq)2K2SO4(aq)+I2(s)
  1. 25.0
  2. 12.5
  3. 33.6
  4. 15.5


Solution

The correct option is A 25.0
In the balanced reaction,
K2S2O8(aq)+2KI(aq)2K2SO4(aq)+I2(s)

1 mol of K2S2O8 requires 2 mol of KI as per stoichiometry.
So, 12.5 mol of K2S2O8 requires 2×12.5 moles=25 mol of KI

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