\( H _{3} C - Br \stackrel{ KCN }{\longrightarrow} Ether \underset{ Ci LiAlH _{4} O ^{+}}{\longrightarrow} \)the product (C) is :
(AIPMT 2012 (PRE))
A
Ethyl alcohol
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B
Acetone
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C
Methane
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D
Actaldehyde
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Solution
The correct option is A Ethyl alcohol Alkyl bromide undergoes nulceophilic substitution reaction with KCN followed by hydrolysis of CN to give COOH and further get reduced to OH group in presence of LiAlH4.
\( KCN \longrightarrow \)
\( H _{3} O ^{+} \)
\( H _{3} C - COOH \)
(A)
(B)
(C)