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Question

In the given circuit the current I is
1815379_6e28b6ffc297439084876ce54bf71bca.png

A
0.4 A
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B
0.4 A
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C
0.8 A
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D
0.8 A
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Solution

The correct option is B 0.4 A
The circuit can be simplified as follows
Applying KCL at junction A
i3=i1+i2 ...(i)
Applying Kirchhoff's voltage law for the loop ABCDA
30i140i3+40=0
30i140(i1+i2)+40=0
7i1+4i2=4 ......(iii)
Applying Kirchhoff's voltage law for the loop ADEFA.
40i240i3+80+40=0
40i240(i1+i2)=120
i1+2i2=3 .....(iii)
On solving equation (ii) and (iii) i1=0.4 A.

1735897_1815379_ans_552b9688f69a44779128f87017145f2f.png

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