In the given circuit, the potential of the point E is

Zero

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-8V

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- 4/3 V

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4/3 V

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Solution

The correct option is C - 4/3 V
The current in the circuit $= \frac{8}{5 + 1} = \frac{4}{3}$
Now $V_{c} - V_{E} = \frac{4}{3} \times 1 \Rightarrow V_{E} = - \frac{4}{3} V .$

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