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Question

In the given circuit with steady current the potential drop across the capacitor must be

A
V
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B
V2
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C
V3
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D
2V3
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Solution

The correct option is

C

V3





In the steady state no current flows in the branch containing the capacitor .Thus the current say l flows in the branches containing R and 2R. Applying Kirchoff's second rule to the loop abcdefa
2V-I(2R)-IR-V=0
I=V3R
Potential drop across capacitor =2V-V-l(2R)=Vv3R× 2R
=V2v3=v3


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