1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# In the given figure AB is parallel to ED. If ∠ABC=160∘ and ∠EDC=130∘ then find the value of x and y.

A

x=90 and y=270

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

x=80 and y=280

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

x=70 and y=290

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

x=60 and y=300

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C x=70∘ and y=290∘ Construction: Draw a line FG through C such that FG∥AB∥ED as shown. ⇒∠ABC+∠BCF=180∘ (Co−interior angles) ⇒∠BCF=180∘−∠ABC ⇒∠BCF=180∘−160∘ ⇒∠BCF=20∘ ⇒∠FCD+∠CDE=180∘ (Co−interior angles) ⇒∠FCD=180∘−∠CDE ⇒∠FCD=180∘−130∘ ⇒∠FCD=50∘ x=∠BCF+∠FCD x=20∘+50∘=70∘ y=360∘−x (Angle about a point) y=360∘−70∘=290∘

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Parallel Lines and a Transversal
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program