In the given figure, ∠ABC = $90^{\circ}$ and BM is a median drawn from B to AC, AB = 8cm and BC = 6 cm. Then, choose the correct option(s).

MC = 5cm.

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AM = 5cm.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

MB = 5cm.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

AC = 5cm.

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Solution

The correct options are
A
MC = 5cm.

B
AM = 5cm.

C
MB = 5cm.

AC = $\sqrt{8^{2} + 6^{2}}$ = $\sqrt{100}$ = 10 cm.

So, AM = MC = 5cm.

Since the mid point of the hypotenuse of a right triangle is equidistant from its vertices, so

BM = AM = MC = 5cm.

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Similar questions

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Q. In the given figure,

△ A B C = 90^{o}

and

B M

is a median,

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and

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. Then, length

B M

is equal to:

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In the given figure, ∠ABC = 90∘ and BM is a median drawn from B to AC, AB = 8cm and BC = 6 cm. Then, choose the correct option(s).

The correct options are A MC = 5cm. B AM = 5cm. C MB = 5cm. AC = √82+62 = √100 = 10 cm. So, AM = MC = 5cm. Since the mid point of the hypotenuse of a right triangle is equidistant from its vertices, so BM = AM = MC = 5cm.

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median drawn from B to AC, AB = 8cm and BC = 6 cm. Then, choose the correct option(s).

The correct options are
A
MC = 5cm.

B
AM = 5cm.

C
MB = 5cm.

AC = $\sqrt{8^{2} + 6^{2}}$ = $\sqrt{100}$ = 10 cm.

So, AM = MC = 5cm.

Since the mid point of the hypotenuse of a right triangle is equidistant from its vertices, so

BM = AM = MC = 5cm.