In the given figure ABC is an isosceles triangle with perimeter 44 cm. The base BC is of the length 12 cm.
Sides AB and AC are congruent. A circle touches the three sides as shown. Find the length of a tangent segment from A to the circle.
AP = AQ, BP = BR and CR = CQ (Tangents from a external point are equal)
Now, AB + AC + BC = 44 cm (Perimeter of triangle ABC)
⇒ AP + BP + AQ + CQ + BC = 44
⇒ AP + BR + AQ + CR + BC = 44
⇒ AP + AQ + BR + CR + BC = 44
⇒ AP + AQ + BC + BC = 44
⇒ 2AP + 2BC = 44
⇒ 2AP = 44 24
∴ AP = 10 cm