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Standard X

Mathematics

Properties of 30°-60°-90° Triangles

In the given ...

Question

In the given figure, AD = ___ cm.

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Solution

In $Δ A E D$ , using pythagoras theorem we have,

$A D^{2} = A E^{2} + E D^{2}$

$A D^{2} = 6^{2} + 8^{2}$

$A D^{2} = 36 + 64$

$A D^{2} = 100$

$A D = 10 c m$

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In the given figure, AD = ___ cm.

In Δ AED, using pythagoras theorem we have, AD2=AE2+ED2 AD2=62+82 AD2=36+64 AD2=100 AD=10 cm

In $Δ A E D$ , using pythagoras theorem we have,

$A D^{2} = A E^{2} + E D^{2}$

$A D^{2} = 6^{2} + 8^{2}$

$A D^{2} = 36 + 64$

$A D^{2} = 100$

$A D = 10 c m$