In the given figure, $∠ A B C = 90^{o}$ and $B D ⊥ A C$
If AB=5.7 cm, BD=3.8 cm and CD=5.4 cm,find BC.\
$[Δ A B C \sim Δ B D C \Rightarrow \frac{A B}{B D} = \frac{B C}{D C}]$

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Solution

$\frac{A B}{B D} = \frac{B C}{D C}$

$\frac{5.7}{3.8} = \frac{B C}{5.4}$

$\frac{3}{2} \times \frac{5.4}{10} = B C$

$B C = \frac{81}{10}$

$B C = 8.1 c m$

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